BSB123 THA 1 Numerical Descriptive Measures (Solutions & Marking Scheme)(2) (1)

.docx
Take Home Assignment 1 Numerical Descriptive Measures Solutions and Marking Scheme (a) (1 mark each) (b) Mean = 38.8 (½ mark) Standard Deviation = 8.7 (½ mark) After sorting in ascending order Q1 = average of obs 36 & 37 = (32.1 + 32.1) / 2 = 32.1 Q2 = average of obs 72 & 73 = (37.9 + 37.9) / 2 = 37.9 Q3 = average of obs 108 & 109 = (44.6 + 45) / 2 = 44.8 (1 mark for each for each quartile) (c) Histogram skewed right with greater spread of probability mass in right tail (1 mark) Since mean (38.8) > Q2 (37.9), the dataset is right skewed. (1 mark) (d) IQR = 44.8 - 32.1 = 12.7 (½ mark) Lower fence: Q1 - 1.5*IQR = 32.1 - 1.5*12.7 = 13.05 (½ mark) Upper fence: Q3 + 1.5*IQR = 44.8 + 1.5*12.7 = 63.85 (½ mark) The are no outliers as all values fall between 13.05 and 63.85 (½ mark) 1
Page1of 1
Uploaded by CountSeaUrchin2334 on coursehero.com