Question
15
(1
point)
Consider
the
two
step
responses
shown
in
the the
graph
below.
Match
them
to
the
Transfer
Functions.
Step
Response
2
—
T
T
T
T
—
Trace
A
18
Trace
B|
|
|
\
1.6
"
-
|
|
|
|
|
it
1
M
N
|
Ill
1\
-
|
|
|
'll
2
'
lIJ
'
.I
\
A
gL
A
'E'
1F
|
|
||
I'
,'
",
o~
4
£
I
T
e
B
A
D
e
a
1
|
SR
A
|'.'
.
:.'..
'-|'
\
o
/..f'.
e
;'i,_,_-;;,.-rf'v-;:—_--_».—r—
—
0.8}
-
\
E
i\
\©
bloe
we
|
\
\//
0.6
I
[
\
\}/
.
|
X
0.4
-'
nl
.
/\
[
|
l
|
20
'l
II
0
E
A
A
!
A
|
0
1
2
3
4
5
6
3
2
B
L'*
Time
(seconds)
7
5
—
w
_—
St
le
3¢
G,(5)=0.9-—
-
(s"
+25+36)
1.
TRACE
A
on
the
Graph
Gs)=09..
36
(45
2.
TRACEBon
the
Graph
T
(P
+25+36)
5