# SPH3U 1.5 (1)

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Task 1: Given: d = 5m, 8 loops present Unknown = λ Equation λ = 2 𝑥 5? / 8 λ = 10/8 λ = 1. 25? Therefore = 1.25m λ 3. Given: total time (0.6s), = 1.25m, d = 5m λ Unknown = speed of wave (v) Equation = v = d/t ? = 5?/0. 6? ? = 8. 3333?/? ?ℎ??????? ? = 8. 3?/? 4. Given: v = 8.3m/s = 1.25m λ Unknown ? equation = v / a ? ? = 8. 3?/? / 1. 25? ? = 6. 64 ℎ𝑧 = 6.6hz ? Therefore = 6.6hz ? '
Task 2: a) Given: L1 = 7.4cm L2 = 22.5cm L3 = 36.7cm = 1200cm T = 21 degrees ? Unknown = λ Equation = λ 2𝐿 / ℎ?????𝑖? ?????? λ = 2 𝑥 7. 4 / 1 λ = 14. 8 λ2 = 2 𝑥 22. 5 / 2 λ2 = 22. 5 λ3 = 2 𝑥 36. 7 / 3 λ3 = 24. 466 ???λ = 24.6+22.5+14.8 3 ???λ = 20. 5 Therefore the average = 20.5cm λ b) Given: f = 1200hz = .205m λ Unknown = v Equation = v = f λ ? = ?λ ? = (1200)(. 205) ? = 246?/? Therefore v = 246m/s c) Unknown = v(room) V = 332 m/s + (.59m/s)21 V = 332 + 12.39 V = 344.39m/s Therefore the theoretical speed of sound (v) according to the temperature of 21 degrees is 344.9m/s
Task 3: a) The Doppler effect is a phenomenon in physics that describes the change in frequency of a wave, such as light or sound. For example, when a sound source approaches, the perceived frequency of the sound increases thus creating a higher pitch while when the sound moves away, the perceived frequency decreases, causing a lower pitch noise. A perfect example of this is an ambulance siren moving towards and away from the person experiencing the Doppler effect. Another application of the Doppler effect would be phone calls. For example, when moving away or towards a cell tower, the frequency of radio waves processing our voice and data changes. b) Given: F source = 400hz, vsource = 20m/s T = 10 degrees C Unknown = f observed v sound Equation = V sound = 332m/s + (0.59m/s) T f observed = f source ( ?????? ?????? + ??????? ) V sound = 332 m/s + (0.59m/s)10 V sound = 332 m/s + 5.9m/s V sound = 337.9m/s Therefore V sound = 337.9m/s in a 10-degree Celsius room f observed = 400 ( 377.9?/? 337.9?/? + 20?/? ) F observed = 400(0.94m/s) F observed = 377.6473hz F observed = 378hz Therefore moving away frequency observed = 378hz F observed = 400 ( 377.9?/? 337.9?/? − 20?/? ) F observed = 400 ( 377.9?/? 337.9?/? − 20?/? ) F observed = 425(1.0629) F observed = 425.165hz F observed = 425hz Therefore the moving towards frequency = 425hz