exercise
Def
we
wate
him
fix)
s
if
we
can
and
me
I
make
the
values
arbitrally
large
positive
,
by
taking
x sumcently
close
to
a
,
but
ecfa

m

factor
(x
4)
x

4
+
2
+
2
x
4
x((5
+
2)
imfe
e
(5
2)
!
"4
x
2
=

is
fo
filled
lim
=(
1)(X
2)
ᶑ
x

>
2
Def
we
say
=a
Is
a
v
A
if
one
at
least
lim
g(x)
DNE
11m
05
m
fix)
os
lim
f(x)
00
x

2
x
>
a
x

a
lim
x

2
+
=
0
m
fix)
os
lim
f(x)
loo

x

>
at
x

a
you
have
to
say
Def
we
write
Im
Rs=
L
If
we
can
x
>


2
make
the
values
of
the
output
vales
of
fex
arbitratrally
close
to
L
,
by
taking
x
sufficently
large
positive
In
the
same
him
fix)
=
L

......

im
f(x)
2
m
fex)
=

3
x

>

00

x

700
↑



Def
we
say
I
is
continuos
at
a
if
m
(x)
=
f(
)
we
say
its
continuos
If
It
Is
example
linear
In
,
poly
,
Sin
,
cos
,
exp
,
log
continous
at
every
put
in
D
Any
combo
of
continus
will
be
If
you
can
draw
grapm
wo
lifting
controus
(+
,
,
,
:)
pencil
FACT
·
m
F(g(x))
=
f
(lim
gc
c)
if
is
continous
x
=
a
x

a