# Lab 3

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/ ''16 · ""' ) ,.f-?Ji Y\ _.c-- '.2-a · S GJ,61~ !11l Phys2425 PRE-LAB FORM EQUILIBRIUM A N D VECTORS: THE FORCE TABLE 1. Four forces , A, B, C, and G, act on a particle leaving it in equilibrium. Given: A= 130 g @ 37° B = 105 g @ 143° C = 55 g @ 90° Determine G by the vector algebraic method for A + B + C + G = 0 ~ 'j \ JC> ,._ ~;n 37° 1 11 · 1 J &] \ Q'::, K ) V\ 31 ° t, , i~ 2. Find G by the graphical method using a scale and a protractor. Use a scale factor of I cm = IO g. Draw arrow heads on vector ends. Result: Length in cm: l q · Cf , G = _1 :,._ 9 ..;._ 9 _.__ _ __._..g @ 2 6 '., 0 33
0 6"' <y G raphical Me J(cii to Find G '::..' IC ti·') .. - - - r "1 , ' ' 1 , 7 I(') /. l,C • - \ r r) V b-"' i .... r ... v v ~F- .,.,l'I '~ ) ~A:;; 130-5 37° 13 :: 105:)@ /Li?> 0 .... :,,. C ~55 j@ qo 0 Phys2425 I'- I' '' _,, ", ,~ I "- I'- 111 t" 1 1'- - I "- "' ,., ' ... I'- 1-" " / - ./ V V ,., v ,, / V / V ./ / ./ 34
r Phys2425 LAB REPORT FORM EQUILIBRIUM A N D VECTORS: THE FORCE TABLE Data Table 1: Determination ofEquilibrant Forces: E, F, G, and S M(kg) M · 9.8 (N) Equilibrant (Mass) (Force) E 0 -1~2 :,916 F 0 , I ~Cf /. 8'52.2.. G 0 ,/98 1 -q ½ o ½ s O · IO?J ,. o oCl ½ Data Table 2: Applied Forces M(kg) M · 9.8 (N) Applied Forces (Mass) (Force) A 0.130 1.27 B 0.105 1.03 - .-..~-~- ~-- · -B 0.105 1.03 C 0.055 0.54 p 0. 105 1.03 0 0.068 0.67 R 0.130 1.27 35 0 (Degree) (Direction) 262 1 85 26 ½ /Y'S 0 (Degree) (Direction) 37° 143° 323° 90° oo ' 50° 240°