9780470458365, Chapter 7.2, Problem 17P

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School
University of Nevada, Las Vegas **We aren't endorsed by this school
Course
ECON 262
Subject
Accounting
Date
Oct 20, 2023
Pages
1
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Chapter 7.2, Problem 17P Step-by-step solution Step1077 Given that 4 -2 3 I -3 0 0 1 A=|-2 1 6|B=|-3 1 0|Cc=|3 2 2 2 0o 0 =2 -2 0 3 a=(1 -2 0)andb=| 1| -1 Step 2077 ABC = (AB) C 4 -2 3)1 -3 0 0 1 =[[-2 1 6{-3 1 0 32 I 2 20 0 -=2)[-2 4+6+0 -12-2+0 0+0-6)0 1 =|=2=-3+0 6+1+0 0+0-12| 3 2 1-6+0 -3+2+0 0+0-4)(-2 0 10 -14 -6 0 1 =-5 7 =12 3 2 5ol 4 )02 0)5, Step 3077 0-42+12 10-28+0 Therefore ABC = | 0+21+24 -5+14+0 0-3+8 -5-2+0 )., -30 -I8 =145 9 50 T e Step4 07 7 4 23 1 -3 0 =2 1 6| [-3 1 0] |0 -20),, 12 235\ 0 0 2)p, 4+6+0 -12-2+0 0+0-6 =[-2-3+40 6+1+0 0+0-12| (I -2 0) 1-6+0 -3+2+0 0+0-4 ), 10 -14 -6 =5 7 -12f (120, =S5 o-l 4 The multiplication of the matrices AB and a is NOT possible .Since, the number of columns in AB is not equal to the number of rows in a. Therefore is undefined. Step 5077 4 23 1 -3 0 3 ABb= |[-2 1 6 -3 1 0 1 12 2),00 0 -2), (-5 4+6+0 -12-2+0 0+0-6 3 =|-2-3+0 6+1+0 0+0-12 1 1-6+0 -3+2+0 0+0-4 -1 10 -14 -6 3 =|-5 7 -12 1 -5 -1 -4 -1 The multiplication of the matrices AB and b is possible .Since, the number of columns in AB is equal to the number of rows in b. Step 6 07 7 30-14+6 Therefore ABb = | —15+7+12 "15-1+4 ) 22 =| 4 -12)54 Step7 077 0 1 Now ca™=[ 3 2| (1 -2 0),, 2 05, 1 1 =3 2 -2 =2 0)5,\0 )5y The multiplication of the matrices C and 47 is NOT possible .Since, the number of columns in C is not equal to the number of rows in o Therefore (5" is undefined.
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